Question

m+(mn²)^1/3+(m²n)^1/3÷m-n×(1-n^1/3÷m^1/3)

Answer 1

Answer:

⇒(m2n)2/3+(mn2)2/3=sin2θ+cos2θ=1

Step-by-step explanation:

m2n=(cosecθ−sinθ)2(secθ−cosθ)=(sinθ1−sin2θ)2(cosθ1−cos2θ)=sin2θcosθcos4θsin2θ

⇒(m2n)=cos3θ

⇒(m2n)2/3=cos2θ

Similarly mn2=(cosecθ−sinθ)(secθ−cosθ)2=cos2θsinθsin4θcos2θ=sin3θ

⇒(m2n)2/3+(mn2)2/3=sin2θ+cos2θ=1.