Question

m(mx + ny)2 + mn (mx + ny) + n (mx + ny)
factorise
​

Answer 1

Answer:

Answer

mx−ny=m

2

+n

2

mx+my=2m

2

- - -

−my−ny=m

2

+n

2

−2m

2

⇒(x+y=2m)×m

−y=

m+n

(n

2

−m

2

)

⇒y=(

m+n

m

2

−n

2

)=

(m+n)

(m+n)(m−n)

y=m−n

Substitute 'y' in equaltion x+y=2m

x=2m−m+n

x=m+n

(x,y)=[m+n,m−n]

solution

Answer 2

SO, THE ANSWER IS (MX+NY) [M²X+MNY+MN+N]