Question

(m+n)^-1 (m^-1+n^-2)=m^x n^y show that: x+y+z=0

Answer 1

Answer:

Step-by-step explanation:

(m+n)-1 (m-1+n-1)=mxny

=) (1/m+n) (1/m+1/n)=mxny

=) (1/m+n) (m+n/mn)=mxny

=) (1/mn)=mxny

=) m-1n-1=mxny

=) x=-1 y=-1

x+y+2=(-1)+(-1)+2=-2+2=0

Hence Proved.

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Answer 2

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