(m+n)(2m-3n) multiply the following binomial and verify the result for m=-2, n=0
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If sin A + cos A = m and sin3A+cos3A=nsin3A+cos3A=n, then (1) m3−3m+n=0m3-3m+n=0 (2) n3−3n+2m=0n3-3n+2m=0 (3) m3−3m+2n=0m3-3m+2n=0 (4) m3+3m+2n=0
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