m + [n ÷ {2m - (m + 2n)}]
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Here is your answer -
m + [n ÷ {2m - (m + 2n)}]
= m + [n ÷ {2m - m - 2n}]
= m + [n ÷ {m - 2n}]
= m + [n × {1/m - 2n}]
= m + [ n/m - 2n]
= m ( m - 2n ) + n / m - 2n
= m² + 2mn + n / m - 2n
Thanks !!!!
m + [n ÷ {2m - (m + 2n)}]
= m + [n ÷ {2m - m - 2n}]
= m + [n ÷ {m - 2n}]
= m + [n × {1/m - 2n}]
= m + [ n/m - 2n]
= m ( m - 2n ) + n / m - 2n
= m² + 2mn + n / m - 2n
Thanks !!!!
Answered by
0
Given m + [ n ÷ { 2m-(m+2n)}]
= m+[ n ÷ { 2m - m - 2n }]
= m + [ n ÷ { m - 2n } ]
= m + [ n/( m - 2n ) ]
= [ m(m - 2n ) + n ]/( m - 2n )
= ( m² - 2mn + n )/( m - 2n )
•••••
= m+[ n ÷ { 2m - m - 2n }]
= m + [ n ÷ { m - 2n } ]
= m + [ n/( m - 2n ) ]
= [ m(m - 2n ) + n ]/( m - 2n )
= ( m² - 2mn + n )/( m - 2n )
•••••
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