Question

(m+n)^3-(m-n)^3-6mn(m^2-n^2)

Answer 1

Step-by-step explanation:

m

3

−n

3

−m(m

2

−n

2

)+n(m−n)

2

=nm

2

−mn

2

Step-by-step explanation:

Given : Expression m^3-n^3-m(m^2-n^2)+n(m-n)^2m

3

−n

3

−m(m

2

−n

2

)+n(m−n)

2

To find : Simplify the expression ?

Solution :

Solving the expression by opening the bracket first,

=m^3-n^3-m^3+mn^2+n(m^2+n^2-2mn)=m

3

−n

3

−m

3

+mn

2

+n(m

2

+n

2

−2mn)

=m^3-n^3-m^3+mn^2+nm^2+n^3-2mn^2=m

3

−n

3

−m

3

+mn

2

+nm

2

+n

3

−2mn

2

=nm^2-mn^2=nm

2

−mn

2

Therefore, m^3-n^3-m(m^2-n^2)+n(m-n)^2=nm^2-mn^2m

3

−n

3

−m(m

2

−n

2

)+n(m−n)

2

=