Question

M,n are two successive shells in hydrogen atom. The radial distance between two successive shells in hydrogen atom is

Answer 1

Answer:

The radial distance between the two successive shells in the hydrogen atom is 0.529$\left(m^{2}-n^{2}\right)$

Explanation:

The formula for the radius of Bohr's orbit for any atom (from the nucleus) will be  

$r_{n}=0.529 A^{\circ}\left(\frac{n^{2}}{2}\right)$

For Hydrogen, Z = 1.

Radius of$n^{t h}$orbit = 0.529 $n^{2}$

Similarly, for $m^{t h}$orbit = 0.529 $m^{2}$

So, it is asked the radical distance between successive orbits of m and n.

The radius is calculated from the nucleus.

Difference between them = 0.529$\left(m^{2}-n^{2}\right)$

Answer 2

Answer:

Explanation:

Energy difference is given by, E=RZ

2

hc[

n

1

2

​

1

​

−

n

2

2

​

1

​

].

Where, R is Rydberg constant for the hydrogen atom.

From this equation, it is clear that on moving away from the nucleus, the energy difference between successive orbits decreases.

So, minimum energy difference will be between two farthest orbits i.e. N, O - shells.

Option D is correct.