Math, asked by questoinarre, 1 year ago

m, n, p are roots of x³-mx²+nx-1=0, then sum of all roots is?​

Answers

Answered by GoKuL3112003
0

sum of roots is -b/a which will be -(-m)/1=m

which also show m=m+n+p

so n+p=0

product of root -d/a which is 1

so m.n.p=1


questoinarre: i asked sum
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