Question

M
N
P
Fig. 2.17
3. In figure 2.18, Z QPR = 90°,
seg PM I seg QR and Q-M-R,
PM = 10, QM = 8, find QR.
*
38​

Answer 1

Answer:

According to Pythagoras theorem in ∆PRM

PM²= PR²+ RM²

RM²=PM²-PR²  

In ∆PRQ

PR²= RQ²+PQ²

PQ²= PR ²+ (RM+MQ)²

PQ²= PR ²+ (RM+RM)²

PQ²= PR ²+ (2RM)²

PQ²= PR ²+ (4RM)²

PQ²= PR ²+ 4(PM²-PR² )

PQ²= PR ²+ 4PM²- 4PR²

PQ²= 4PM²- 3PR²