Question

m+nP2=42, and m-nP2=6 then the value s of m and n are_____​

Answer 1

Hi mate,

m+nP2=90 and m−nP2=30 Let m+n = a and m−n = b aP2=90 or a!(a−2)!=90a(a−1)(a−2)!(a−2)!= 90 a(a−1)= 90= 10×9 so a = 10m+n=10 .....(1)Again,bP2=30 or b!(b−2)!=30b(b−1)(b−2)!(b−2)!= 30 b(b−1)= 30= 6×5 so b= 6m−n=6 .....(2)Adding equation 1 and 2, 2m = 16m = 8 and hence n = 10−m = 2

I hope u understand

Answer 2

Answer:

m+nP2=42

m-nP2=6

Then,

m=5 and n=2