Chemistry, asked by madhupandey5080, 2 days ago

M.O diagram of Ne2 Calculate bond order

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Answered by sourav0667
0

Answer:

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Class 11

>>Chemistry

>>Chemical Bonding and Molecular Structure

>>Molecular Orbital Theory

>>Use the molecular orbital energy level d

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Use the molecular orbital energy level diagram to show that N

2

would be expected to have a triple bond, F

2

, a single bond and Ne

2

, no bond.

Hard

Solution

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Formation of N

2

molecule: Electronic Configuration,

σ1s

2

<σ∗1s

2

<σ2s

2

<σ∗2s

2

<[π2p

x

2

=π2p

x

2

]<<σ2p

z

2

Bond order = (N

b

−N

a

)/2=(10−4)/2=3

Bond order indicates the number of bonds in diatomic molecule is 3, hence TripleBond

Formation of F

2

molecule: Electronic Configuration:

σ1s

2

<σ∗1s

2

<σ2s

2

<σ∗2s

z

2

σ∗2pz

2

<[π2p

x

2

=π2p

x

2

]<[π∗2p

x

2

=π∗2p

x

2

]<σ2p

z

Bond order = (N

b

−N

a

)/2=(10−8)/2=1

Single bond F−F.

Formation of Ne

2

molecule: Electronic Configuration,

σ1s

2

<σ∗1s

2

<σ2s

2

<σ∗2s

z

2

<σ∗2pz

2

<[π2p

x

2

=π2p

x

2

]<[π∗2p

x

2

=π∗2p

x

2

]<σ2p

z

2

Bond order = (N

b

−N

a

)/2=(10−10)/2=0

Hence, no bond between Ne atoms

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