Question

m power n = 121 ,then {m-1} power n and + digit 1 is

Answer 1

$given \: that \\ {m}^{n} = 121 \\ {11}^{2} = 121 \\ m = 11 \\ n = 2 \\ then \\ m - 1 = 11 - 1 = 10 \\ m + 1 = 11 + 1 = 12$