Question

m sq-14m+13=0 give the solution of a quadrantic equation by competing the square​

Answer 1

Explanation:

$m ^{2} - 14m + 13 = 0 \\ m ^{2} - m - 13m + 13 = 0 \\ m(m - 1) - 13(m - 1) = 0 \\ (m - 1)(m - 13) = 0 \\ m = 1 \\ m = 13$

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