Question

m square + 6 m - 16 through middle term splitting

Answer 1

Step-by-step explanation:

m^2+6m+16

now we will take the constant terms of the first and last term

I.e. 1&-16

1×(-16)=-16

Now we need to look forward for two numbers whose sum or difference is 6(for splitting 6m) and product is 16.

-2×8=16

-2+8=6

m^2+(-2m)+(8m)-16

(m^2-2m)+(8m-16)

m(m-2)+8(m-2)

thus, final answer=

(m+8)(m-2)

Hope it helps✌️