m tan (a-theta)÷cos ka scoured = n tan theta÷ cos ka squre (a-theta)
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tan(m theta) = tan(n theta)
Take the inverse tangent of both sides:
m theta = N theta + pi N for N belongs to Z
Subtract b theta from both sides:
theta (m-n) = pi N for N belongs to Z
Divide both sides by m-n:
theta = (pi N)/(m-n) for N belongs to Z
so, putting value of N=1, theta=pi/(m-n)
putting value of N=2, theta=2pi/(m-n) and so on..
so the values of theta form an ap
and common difference = (N+1)pi/(m-n)-N pi/(m-n)=pi/(m-n)
Therefore,proved that values of theta form an AP with common difference pi/(m-n)
Hope this will help u.
Take the inverse tangent of both sides:
m theta = N theta + pi N for N belongs to Z
Subtract b theta from both sides:
theta (m-n) = pi N for N belongs to Z
Divide both sides by m-n:
theta = (pi N)/(m-n) for N belongs to Z
so, putting value of N=1, theta=pi/(m-n)
putting value of N=2, theta=2pi/(m-n) and so on..
so the values of theta form an ap
and common difference = (N+1)pi/(m-n)-N pi/(m-n)=pi/(m-n)
Therefore,proved that values of theta form an AP with common difference pi/(m-n)
Hope this will help u.
sagarKumar111:
galat
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