Question

m = Tan135 then m =?​

Answer 1

Answer:

m=-1

Step-by-step explanation:

$\tan(180 - 45 ) = - 1$

Answer 2

Step-by-step explanation:

You can solve this in two ways.

You can solve this in two ways.First way:-

You can solve this in two ways.First way:-tan(90+¢)°= -cot(¢)°

You can solve this in two ways.First way:-tan(90+¢)°= -cot(¢)°Also,

You can solve this in two ways.First way:-tan(90+¢)°= -cot(¢)°Also,cot(-¢)° = -cot(¢)°

You can solve this in two ways.First way:-tan(90+¢)°= -cot(¢)°Also,cot(-¢)° = -cot(¢)°So, I can write tan135° as tan(90+45)°

You can solve this in two ways.First way:-tan(90+¢)°= -cot(¢)°Also,cot(-¢)° = -cot(¢)°So, I can write tan135° as tan(90+45)°if we put this in formula we will get:-

You can solve this in two ways.First way:-tan(90+¢)°= -cot(¢)°Also,cot(-¢)° = -cot(¢)°So, I can write tan135° as tan(90+45)°if we put this in formula we will get:-tan(90+45)° = -cot(45)° =-1, because cot(45)°=1

You can solve this in two ways.First way:-tan(90+¢)°= -cot(¢)°Also,cot(-¢)° = -cot(¢)°So, I can write tan135° as tan(90+45)°if we put this in formula we will get:-tan(90+45)° = -cot(45)° =-1, because cot(45)°=1So, tan(135)° =-1

You can solve this in two ways.First way:-tan(90+¢)°= -cot(¢)°Also,cot(-¢)° = -cot(¢)°So, I can write tan135° as tan(90+45)°if we put this in formula we will get:-tan(90+45)° = -cot(45)° =-1, because cot(45)°=1So, tan(135)° =-1Second way:-

You can solve this in two ways.First way:-tan(90+¢)°= -cot(¢)°Also,cot(-¢)° = -cot(¢)°So, I can write tan135° as tan(90+45)°if we put this in formula we will get:-tan(90+45)° = -cot(45)° =-1, because cot(45)°=1So, tan(135)° =-1Second way:-tan(180–¢)°=-tan(¢)°

You can solve this in two ways.First way:-tan(90+¢)°= -cot(¢)°Also,cot(-¢)° = -cot(¢)°So, I can write tan135° as tan(90+45)°if we put this in formula we will get:-tan(90+45)° = -cot(45)° =-1, because cot(45)°=1So, tan(135)° =-1Second way:-tan(180–¢)°=-tan(¢)°Also,

You can solve this in two ways.First way:-tan(90+¢)°= -cot(¢)°Also,cot(-¢)° = -cot(¢)°So, I can write tan135° as tan(90+45)°if we put this in formula we will get:-tan(90+45)° = -cot(45)° =-1, because cot(45)°=1So, tan(135)° =-1Second way:-tan(180–¢)°=-tan(¢)°Also,tan(¢)° = -tan(¢)°

You can solve this in two ways.First way:-tan(90+¢)°= -cot(¢)°Also,cot(-¢)° = -cot(¢)°So, I can write tan135° as tan(90+45)°if we put this in formula we will get:-tan(90+45)° = -cot(45)° =-1, because cot(45)°=1So, tan(135)° =-1Second way:-tan(180–¢)°=-tan(¢)°Also,tan(¢)° = -tan(¢)°So, I can write tan135° as tan(180-45)°

You can solve this in two ways.First way:-tan(90+¢)°= -cot(¢)°Also,cot(-¢)° = -cot(¢)°So, I can write tan135° as tan(90+45)°if we put this in formula we will get:-tan(90+45)° = -cot(45)° =-1, because cot(45)°=1So, tan(135)° =-1Second way:-tan(180–¢)°=-tan(¢)°Also,tan(¢)° = -tan(¢)°So, I can write tan135° as tan(180-45)°If we put thia in formula we will get:-

You can solve this in two ways.First way:-tan(90+¢)°= -cot(¢)°Also,cot(-¢)° = -cot(¢)°So, I can write tan135° as tan(90+45)°if we put this in formula we will get:-tan(90+45)° = -cot(45)° =-1, because cot(45)°=1So, tan(135)° =-1Second way:-tan(180–¢)°=-tan(¢)°Also,tan(¢)° = -tan(¢)°So, I can write tan135° as tan(180-45)°If we put thia in formula we will get:-tan(180–45)° = -tan(45)° = -1, because tan(45)° =1

You can solve this in two ways.First way:-tan(90+¢)°= -cot(¢)°Also,cot(-¢)° = -cot(¢)°So, I can write tan135° as tan(90+45)°if we put this in formula we will get:-tan(90+45)° = -cot(45)° =-1, because cot(45)°=1So, tan(135)° =-1Second way:-tan(180–¢)°=-tan(¢)°Also,tan(¢)° = -tan(¢)°So, I can write tan135° as tan(180-45)°If we put thia in formula we will get:-tan(180–45)° = -tan(45)° = -1, because tan(45)° =1So, tan(135)°=-1

You can solve this in two ways.First way:-tan(90+¢)°= -cot(¢)°Also,cot(-¢)° = -cot(¢)°So, I can write tan135° as tan(90+45)°if we put this in formula we will get:-tan(90+45)° = -cot(45)° =-1, because cot(45)°=1So, tan(135)° =-1Second way:-tan(180–¢)°=-tan(¢)°Also,tan(¢)° = -tan(¢)°So, I can write tan135° as tan(180-45)°If we put thia in formula we will get:-tan(180–45)° = -tan(45)° = -1, because tan(45)° =1So, tan(135)°=-1In both the cases we got answer as 1.

:.m=1

Thanks!

hope it will help you........