m the distance between 0 and
The radius of the circle is 25 cm. Find the position of A. B and C. if
b. OB is 28 cm
a. OA is 14 cm
c. oC is 25 c
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Answer:
In ΔABC,
Angle in a semicircle, ∠C=90°
Therefore, by Pythagoras theorem
BC² +AC² =AB²
BC²+12²=13²
BC²=169−144=25
BC=5
Area of shaded region = Area of semicircle – Area of triangle
=1/2πr²-1/2bh
=1/2 × 3.14 × (13/2)² - 1/2 × 5 × 12
=3.14×13×13/2×4 - 30
Area of shaded region =36.39 cm².
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