Question

m with constant tangential acceleration. If the
velocity of the particle is 80 m/s at the end of
the second revolution after motion has begun,
the tangential acceleration is​

Answer 1

Answer:

40 m/s²

Explanation:

r = $\frac{20}{\pi }$ m

v = 80 m/s

θ = 2 revolutions = 4π rad.

Using Equation :

ω² = ω₀² + 2αθ     ..(ω₀=0)

ω² = 2αθ     ..(ω=v/r  &  a=rα)

a = v²/2rθ

a = 40 m/s²