Question

m^x+ + mno4^- ==> mo3^- + mn^2+ + 1/2O2 if one mole of mno4^- oxidises 2.5 moles of m^x+. Find value of x

Answer 1

Answer:

Value of x is ''2''.

Explanation:

Mn7+ + Mx+ →Mn2+  + MNo. of equivalents of MnO4− = No. of equivalents of Mmoles ×valency factor=No. of equivalentsso 1×5 = 2.5×valency factor of Mvalency factor of M=2It means the oxidation No. change for Mx+ → M is 2.