Physics, asked by hussainsajjad1445, 11 months ago

[M¹L¹T⁻¹] is an expression for _______.(A) force (B) energy(C) pressure (D) momentum

Answers

Answered by abhi178
1

answer : option (D) momentum

explanation : let's check options one - by - one.

option (A) we know, force = mass × acceleration

so, dimension of force = dimension of mass × dimension of acceleration

= [M1][L¹T-²] = [M¹L¹T-²] , obviously, it is not the answer.

option (B) energy = workdone = force × displacement

dimension of energy = dimension of force × dimension of displacement

= [M¹L¹T-²] × [L¹] = [M¹L²T-²] , it is not same as above mentioned.

option (C), pressure = force/area

so, dimension of pressure = [M¹L¹T-²]/[L²]= [M¹L-¹T-²] , no it's not correct.

option (D), momentum = mass × velocity

so, dimension of momentum = [M¹][L¹T-¹]= [M¹L¹T-¹],

hurray ! we got it, dimension of momentum is same as above mentioned.

hence, option (D) is correct.

Answered by nalinsingh
1

Answer:

Explanation:

Option - D Momentum

Because we known that momentum = mass * velocity

(M-1) [L^1T^-1] = [M¹L¹T⁻¹]

Hence, option D is the correct answer.

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