Question

m1v1+m2v2)= (m1u1+ m2u2) This formula represents

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Answer 1

Answer:

The principle of conservation of momentum can be used in two dimensions by expressing the velocities in vector form to obtain: m1u1 + m2u2 = m1v1 + m2v2. ... The velocity of particle A before the collision was (4i − 3j)ms−1 and the velocity of particle B before the collision was (4i + 4j) m s−1.

Answer 2

Answer:

The law of conservation of momentum.

Explanation:

Since (m1 u1  + m2 u2 ) is the total momentum  of the two objects 1 and 2 before the collision  and (m1 v1 + m2v2) is their total momentum

after the collision, we observe  that the total momentum of the two object

remains unchanged or conserved provided no  other external force acts.

As a result of this ideal collision  experiment, we say that the sum of momenta  of the two objects before collision is equal to  the sum of momenta after the collision  provided there is no external unbalanced  force acting on them. This is known as the  law of conservation of momentum