Зm2 + 2m- 7 = 0
Solve using formula
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Step-by-step explanation:
√D = √88 = √2×2 × 2 ×11 = 2√22 . => 1 - √22/3 , 1 + √22 /3. Hence, ( 1 - √22/3) and ( 1 + √22/3) are the two zeroes of the given quadratic equation
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