Question

m2-3m-1=0.
solve the quadratic equation
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Answer 1

Answer:

${m}^{2} - 3m - 1 = 0 \\ a = 1 \: b = - 3 \: \: c = - 1 \\ d = {b}^{2} - 4ac \\ = { - 3}^{2} - 4 \times 1 \times - 1 \\ = 9 + 4 \\ = 13 \\ m = \frac{ - b - \sqrt{d} }{2a} \: \: \: \: m = \frac{ - b + \sqrt{d} }{2a} \\ m = \frac{ - ( - 3) - \sqrt{13} }{2 \times 18} \: \: \: \: \: m = \frac{ - ( - 3) + \sqrt{13} }{2 \times 1} \\ m = \frac{ 3 - \sqrt{13} }{2} \: \: \: \: \: m = \frac{3 + \sqrt{13} }{2}$

Answer 2

Answer:

Answer:

▶ m= 3 +√13/2

▶▶ and m= 3-√13/2

Step-by-step explanation:

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