Question

m2 + 4n2 + 4mn - 16 factorise

Answer 1

Answer:

(m+2n+4)(m+2n-4)

Step-by-step explanation:

m² + 4n² + 4mn - 16

= (m+2n)² - (4)²

= (m+2n+4)(m+2n-4)

Answer 2

(m+2n + 4)(m+ 2n-4)

Step-by-step explanation:

${m}^{2} + {4n}^{2} + 4mn - 16 \\ {m}^{2} + {(2n)}^{2} + 2 \times m \times 2n - {4}^{2}$

now using

${x}^{2} + {y}^{2} + 2xy = {(x + y)}^{2}$

x= m

y= 2n

${(m + 2n)}^{2} - {4}^{2}$

now using

${x}^{2} - {y}^{2} = (x + y)(x - y)$

x= m +2n

y = 4

= (m+2n + 4)(m+ 2n-4)

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