Question

m²-5m=-3 solve by square method
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Answer 1

m2-5m+3=0

b2-4ac

=25-12

=13

m=-b+or-√b2-4ac/2a

m=5+or-√13/2

Answer 2

$\sf{\huge{\red{\underline{Answer}}}}$

Given

m² - 5m = -3

by making RHS zero

=> m² - 5m + 3 = 0

Now by using Sridhacharyas formula which is

$\frac{-b±\sqrt{b^2-4ac}}{2a}$

by putting values of coefficients

= $\frac{5± \sqrt{5^2 - 4 × 1 × 3 }}{2× 1}$

= $\frac{5± \sqrt{25 - 12 }}{2}$

= $\frac{5 ± \sqrt{13}}{2}$

or values of m

= $\frac{5+\sqrt{13}}{2} \: and\: \frac{5 - \sqrt{13}}{2}$

or factorization

= (m - $\frac{5+\sqrt{13}}{2}$ ) (m - $\frac{5-\sqrt{13}}{2}$ )

Hope it helps