Question

(M²_7M-11) (mas) send solution​

Answer 1

Answer:

M= (7+√94)/2 & M= (7-√94)/2

Step-by-step explanation:

Given that,

(M^2-7M-11)=0

there is a formula I.e;

for the equation ax²+bx+c=0 x=[-b±√(b²-4ac)]/2a

Here,a=1,b=-7,c=-11,x=M

Now,

M=[-(-7)±√((-7)²-4(1)(-11))]/2(1)

M=[7±√(49+44)]/2

M=(7±√94)/2

M=(7+√94)/2 & M=(7-√94)/2

HOPE THIS WOULD BE HELPFUL FOR YOU