Question

m²+8m_48=0 by factorization method​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

${m}^{2} + 8m - 48 = 0 \\ \\ = > {m}^{2} + (12 - 4)m - 48 = 0 \\ \\ = > {m}^{2} + 12m - 4m - 48 = 0 \\ \\ = > m(m + 12) - 4(m + 12) = 0 \\ \\ = > (m + 12)(m - 4) = 0 \\ \\ either \: m + 12 = 0 \\ \\ = > m = - 12 \\ \\ or \: m - 4 = 0 \\ \\ = > m = 4$

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