m²-(m+3)(m+4) = 24
(2m+1)
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The given sequence is an Arithmetic Progression. The difference between the two terms is constant.
t1 = m+2, (first term)
t2 = 4m -6 (second term)
t3 = 3m-2 (Third term)
t2-t1= t3-t2
(4m-6)-(m+2) = (3m-2)-(4m-6)
4m-6-m-2 = 3m-2–4m+6
4m-m-6–2= 3m-4m +6–2
3m - 8 = -m +4
3m+m = 8+4
4m = 12
m= 12/4 = 3
m = 3
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