Question

m²+m-72 factorise the equation..

Answer 1

Answer:

$m {}^{2} + 9m - 8m - 72 = 0 \\ = > m(m + 9) - 8(m + 9) = 0 \\ = > (m + 9)(m - 8) = 0 \\ = > m + 9 = 0 \: or \: m - 8 = 0 \\ = > m = - 9 \: or \: m = 8$

Answer 2

The factorization is $(m-8)(m+9)$.

• The positive integers that can divide a number evenly are known as factors in mathematics. Let's say we multiply two numbers to produce a result. The product's factors are the number that is multiplied. Each number has a self-referential element.
• There are several examples of factors in everyday life, such putting candies in a box, arranging numbers in a certain pattern, giving chocolates to kids, etc. We must apply the multiplication or division method in order to determine a number's factors.
• The numbers that can divide a number exactly are called factors. There is therefore no residual after division. The numbers you multiply together to obtain another number are  called factors. A factor is therefore another number's divisor.

Here, the expression is given as,

$m^{2} +m-72$.

Now, by applying middle term break, we get,

$m^{2} +9m-8m-72$

Or, $m(m+9)-8(m+9)$

Or, $(m-8)(m+9)$

Hence, the factorization is $(m-8)(m+9)$.

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