Math, asked by 369333, 11 months ago

m²-n²/(m+n) ² ×m²mn+n²/m³-n²​

Answers

Answered by deviurmila017
5

in my book that is question

m^2-n^2/(m+n)^2×m^2+mn+n^2/m^3-n^3

Step-by-step explanation:

=(m-n)(m+n)/m+n)^2 × m^2+mn+n^2/m^3-n^3

=(m-n)/(m+n) ×m^2+mn+ n^2/(m-n)(m^2+mn+n^2)

=1/m+n

if that is question so it is solutions

if not so sorry

Similar questions