Math, asked by sonusharma138, 7 months ago

m²n²(2m-n²)-mn²(4mn-2m²)+m³n(4-3n)​

Answers

Answered by Anonymous
6

Answer:

m^2 n(mn-n^3+4m)

Step-by-step explanation:

(2m^3 n^2-m^2 n^4) - (4m^2 n^3+2m^3 n^2) + (4m^3 n-3m^3 n^2)

so,(1m^3 n^2)-(m^2 n^4)+(4m^3n)

m^2 n(mn-n^3+4m) [by taking common]

hope it helps you...

Answered by Anonymous
0

answer is the attachment...!!!

# Hope it helps you ☺☺

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