m²n²(2m-n²)-mn²(4mn-2m²)+m³n(4-3n)
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Answered by
6
Answer:
m^2 n(mn-n^3+4m)
Step-by-step explanation:
(2m^3 n^2-m^2 n^4) - (4m^2 n^3+2m^3 n^2) + (4m^3 n-3m^3 n^2)
so,(1m^3 n^2)-(m^2 n^4)+(4m^3n)
m^2 n(mn-n^3+4m) [by taking common]
hope it helps you...
Answered by
0
answer is the attachment...!!!
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