Question

m²n²-4mn+4-x², Factorize the given equation.

Answer 1

(mn-2)^2-x^2
(mn-2+x)(mn-2-x)
(mn+x-2)(mn-x-2)

Answer 2

Answer:

( mn-2+x )( mn-2-x )

Step-by-step explanation:

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We know the algebraic identities:

i ) a² - 2ab + b² = ( a - b )²

ii ) p² - q² = ( p + q )( p - q )

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m²n²-4mn+4-x²

= [(mn)² - 2(mn)×2+2²] - x²

= ( mn - 2 )² - x²

= ( mn -2 + x )( mn - 2 - x )

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