Question

m³+3m²+2m+14 find value of m​

Answer 1

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$\tt{ m^3 + 3m^2 + 2m + 14 = 0}$

$\tt{ m ( m^2 + 3m + 2 ) + 14 = 0 }$

$\tt{ m = - 14 }$

$\tt{ m^2 + 2m + m + 2 }$

$\tt{ m ( m + 2 ) + 1 ( m + 2 ) }$

$\tt{ m = - 1 , m = - 2 }$

$\boxed{ m = - 14 , - 1 , - 2 }$

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