Question

m3-7m-6=0 facter solve t
$m {3 - 7m - 6 = 0}^{}$
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Answer 1

Answer:

m^3 - 7m - 6 = 0

Factors of 6 = $\tt{\pm1, \pm2, \pm3, \pm6}$

When m = -1:

=> (-1)^3 - 7(-1) - 6

=> -1 + 7 - 6

=> 0

Thus, m = -1

=>m + 1 = 0 is a factor of p(m)

When m = -2:

=> (-2)^3 - 7(-2) - 6

=> -8 + 14 - 6

=> 0

Thus, m = -2

=> m + 2 = 0 is a factor of p(m)

When m = 3:

=> (3)^3 - 7(3) - 6

=> 27 - 21 - 6

=> 0

Thus, m = 3

=> m - 3 = 0 is a factor of p(m)

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Now, we know that a cubic polynomial can have maximum only 3 factors.

Thus, we can say that:

m^3 - 7m - 6 = (m + 2)(m + 1)(m - 3)

These are the factors of p(m).

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