m3-m2n-n2 by m2 divide
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Answered by
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m3+n but I 'm not sure.........
Answered by
1
THE SUM: m3-mn2+m2n-n3+m2-n2
SOLUTION:
Arranging the terms,
=m3-m2n+m2-n3-mn2-n2
Taking m2 common from
the first three terms and n2 common from the rest three terms,
=m2(m-n+1) + n2(m-n+1)
Taking (m-n+1)
common,
We get,
= (m-n+1)(m2+n2)
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