Question

m⁴-16 factorise using identities
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Answer 1

Answer:

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Answer 2

Given :- m^4 - 16

Solution :-

$\therefore m^4 - 16$

$\implies (m^2)^2 - (4)^2$

Using Identity,

$a^2 - b^2 = (a + b) (a - b)$

We get,

$\implies (m^2 - 4) (m^2 + 4)$

$\implies [(m)^2 - (2)^2] [m^2 + 4]$

Again, Using identity,

$a^2 - b^2 = (a + b) (a - b)$

We get,

$\implies \bf (m - 2) (m + 2) (m^2 + 4)$