m⁴+8m²+16=0 factorize
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Answer:
Step by step solution :
Step 1 :
Equation at the end of step 1 :
((m4) + 23m2) + 16 = 0
Step 2 :
Trying to factor by splitting the middle term
2.1 Factoring m4+8m2+16
The first term is, m4 its coefficient is 1 .
The middle term is, +8m2 its coefficient is 8 .
The last term, "the constant", is +16
Step-1 : Multiply the coefficient of the first term by the constant 1 • 16 = 16
Step-2 : Find two factors of 16 whose sum equals the coefficient of the middle term, which is 8 .
-16 + -1 = -17
-8 + -2 = -10
-4 + -4 = -8
-2 + -8 = -10
-1 + -16 = -17
1 + 16 = 17
2 + 8 = 10
4 + 4 = 8 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 4 and 4
m4 + 4m2 + 4m2 + 16
Step-4 : Add up the first 2 terms, pulling out like factors :
m2 • (m2+4)
Add up the last 2 terms, pulling out common factors :
4 • (m2+4)
Step-5 : Add up the four terms of step 4 :
(m2+4) • (m2+4)
Which is the desired factorization
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