M4
] Solve:-
In parallelogram ABCD, LA = ( 3x + 12 )*_B = ( 2x - 32 ) then find the value of x
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corresponding angles of a parallelogram supplementary
:. angleA +angleB=180⁰
:. (3x+12) + (2x-32) =180⁰
:. 3x+12+2x-32=180⁰
:. 5x - 20 = 180⁰
:. 5x = 180+20
:. x = 200/5
:. x = 40
:.angleA=3x+12 =3(40)+12=132
:.angleB=2x-32 =2(40)-32=48
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