Math, asked by sagarnath2003, 5 months ago

MA
Find the value:
(i) sin 78º – sin 18° + sin 30° – sin 42°​

Answers

Answered by Anonymous
1

Answer:

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Step-by-step explanation:

sin78-sin18+sin30-sin42

= sin78-sin42-sin18+sin30

= 2cos(120/2).sin18-sin18+sin30

= 2cos60.sin18-sin18+sin30

= (2×1/2).sin18-sin18+sin30

= sin18-sin18+1/2

=1/2

Answered by amanyadav15041977
3

Answer:

If A+B=90

, then

sinAsecB

tanA.tanB+tanAcotB

cos

2

A

sin

2

B

=tanA

View Answer

2cos

2

A

1−sinA

±

1+sinA

, when

2

A

=−140

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