मैं हमान किसी से प्यारा होता है
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Answer:
\huge\boxed{\fcolorbox{red}{orange}{Solution:}}
Solution:
\begin{gathered}Let\ the\ two\ no.\ be\ x\ and\ x+1\\ A/Q\\ (x)(x+1)=600\\ = > {x}^{2} +x=600\\ = > {x}^{2} +x-600=0\end{gathered}
Let the two no. be x and x+1
A/Q
(x)(x+1)=600
=>x
2
+x=600
=>x
2
+x−600=0
Hence,option b is correct..
thanks for the free points...
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