Question

मैक्सिमम वैल्यू ऑफ साइन थीटा प्लस कोस थीटा​

Answer 1

Answer:

Let E=sin(x)cos(x)=2⋅sin(x)cos(x)2=sin(2x)2

Now, - 1≤sin(θ)≤1∀θ∈R

Assuming, x∈R , it follows

−1≤sin(2x)≤1∀x∈R

⟹−12≤sin(2x)2≤12⟹−12≤E≤12

Hence, the greatest value that E can attain is 12 .

Step-by-step explanation:

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