Question

मान ज्ञात कीजिए
(-2)⁶÷(-2)³
​

Answer 1

Answer

-8 is the correct answer

Answer 2

Step-by-step explanation:

Since the power of 6 is even, the result will be positive.

$\tt= {2}^{6}\div {(-2)}^{3}$

Simplify ${2}^{6}$ to 64.

$\\ = \tt64\div {(-2)}^{3}$

Since the power of 3 is odd, the result will be negative.

$\tt = 64\div -{2}^{3}$

=64÷ −8

=−8

$\\ \rule{300pt}{0.1pt}$

$\\ \begin{array}{l :l} \tt \sin \left(4 \tan ^{-1} \dfrac{1}{3}\right) & \tan ^{-1} \dfrac{1}{3}=\theta \\ =\sin (4 \theta) & \therefore \tan \theta=\dfrac{1}{3} \\ =\dfrac{2 \tan 2 \theta}{1+\tan ^{2} 2 \theta} & \tan 2 \theta=\dfrac{2\left(\dfrac{1}{3}\right)}{1-\dfrac{1}{9}} \\ =\dfrac{2\left(\dfrac{3}{4}\right)}{1+\dfrac{9}{16}}=\dfrac{24}{25} & =\dfrac{6}{8}=\dfrac{3}{4} \end{array}$