मास ऑफ 5kg डिसेंडिंग भट्टी काली ड्रोसॉफिला शॉप 3KG बाय मींस ऑफ लाइटस्ट्रीम पासिंग बरेली
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Answered by
0
Answer:
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Answered by
1
Answer:
Assuming no friction between plank and block.
By momentum conservation ,
⇒1v=5u
⇒v=5u
energy conservation when spring is at neutral position.
⇒
2
1
kx
2
=
2
1
mu
2
+
2
1
m
2
v
2
2
1
×100×1
2
=
2
1
×5×u
2
+
2
1
×1×(5u)
2
100=30u
2
⇒u
2
=
30
100
=
3
10
⇒u=
3
10
.
Hence, the answer is
3
10
Explanation:
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