Question

मुदा अल्पावधित नष्ट होऊ नये म्हणून उपाय सुचवा​

Answer 1

Explanation:

Answer:

Given :-

A father is 30 years older than his son, however, he will be only thrice as old as the son after 5 years.

To Find :-

What is the father's present age.

Solution :-

Let,

$\mapsto \bf{Present\: age\: of\: son\: =\: x\: years}$

$\mapsto \bf{Present\: age\: of\: father =\: (x + 30)\: years}$

After 5 years :

$\leadsto$ Present age of son = (x + 5) years

$\leadsto$ Present age of father :

$\leadsto \sf x + 30 + 5\: years$

$\leadsto \sf\bold{\green{x + 35\: years}}$

According to the question,

$\implies \sf 3(x + 5) =\: x + 35$

$\implies \sf 3x + 15 =\: x + 35$

$\implies \sf 3x - x =\: 35 - 15$

$\implies \sf 2x =\: 20$

$\implies \sf x =\: \dfrac{20}{2}$

$\implies \sf \bold{\purple{x =\: 10\: years}}$

Hence, the required present ages are :

➲ Present age of son :

$\longrightarrow \sf Present\: Age_{(Son)} =\: x\: years$

$\longrightarrow \sf\bold{\red{Present\: Age_{(Son)} =\: 10\: years}}$

➲ Present age of father :

$\longrightarrow \sf Present\: Age_{(Father)} =\: (x + 30)\: years$

$\longrightarrow \sf Present\: Age_{(Father)} =\: (10 + 30)\: years$

$\longrightarrow \sf\bold{\red{Present \: Age_{(Father)} =\: 40\: years}}$

${\small{\bold{\underline{\therefore\: The\: present\: age\: of\: father\: is\: 40\: years\: .}}}}$

Answer:

Given :-

The perimeter of a rectangle is same as the perimeter of a square of side 12 cm.

The length of the rectangle is 13 cm.

To Find :-

What is the breadth.

Formula Used :-

$\clubsuit$ Perimeter of a rectangle Formula :

$\small\mapsto \sf\boxed{\bold{\pink{Perimeter_{(Rectangle)} =\: 2(Length + Breadth)}}}$

$\clubsuit$ Perimeter of square Formula :

$\mapsto \sf\boxed{\bold{\pink{Perimeter_{(Square)} =\: 4a}}}$

where,

a = Side of Square

Solution :-

Let,

$\mapsto \bf{Breadth\: of\: rectangle =\: x\: cm}$

Given :

Side of square = 12 cm

Length of the rectangle = 13 cm

According to the question by using the formula we get,

$\small\bigstar\: \: \sf\bold{\purple{Perimeter\: of\: Rectangle =\: Perimeter\: of\: Square}}$

$\longrightarrow \sf 2(Length + Breadth) =\: 4a$

$\longrightarrow \sf 2(13 + x) =\: 4(12)$

$\longrightarrow \sf 2(13 + x) =\: 4 \times 12$

$\longrightarrow \sf 26 + 2x =\: 48$

$\longrightarrow \sf 2x =\: 48 - 26$

$\longrightarrow \sf 2x =\: 22$

$\longrightarrow \sf x =\: \dfrac{\cancel{22}}{\cancel{2}}$

$\longrightarrow \sf x =\: \dfrac{11}{1}$

$\longrightarrow \sf\bold{\red{x =\: 11\: cm}}$

${\small{\bold{\underline{\therefore\: The\: breadth\: of\: rectangle\: is\: 11\: cm\: .}}}}$

Answer:

Given :-

The ratio of two numbers is 5 : 6.

8 is adding to each of the number make their ratio 7 : 8.

To Find :-

What are the numbers.

Solution :-

Let,

$\mapsto \bf{First\: number =\: 5x}$

$\mapsto \bf{Second\: number =\: 6x}$

According to the question,

$\implies \sf \dfrac{5x + 8}{6x + 8} =\: \dfrac{7}{8}$

By doing cross multiplication we get,

$\implies \sf 7(6x + 8) =\: 8(5x + 8)$

$\implies \sf 42x + 56 =\: 40x + 64$

$\implies \sf 42x - 40x =\: 64 - 56$

$\implies \sf 2x =\: 8$

$\implies \sf x =\: \dfrac{\cancel{8}}{\cancel{2}}$

$\implies \sf\bold{\purple{x =\: 4}}$

Hence, the required numbers are :

➲ First Number :

$\longrightarrow \sf First\: number =\: 5x$

$\longrightarrow \sf First\: number =\: 5 \times 4$

$\longrightarrow \sf\bold{\red{First\: number =\: 20}}$

➲ Second Number :

$\longrightarrow \sf Second \: number =\: 6x$

$\longrightarrow \sf Second\: number =\: 6 \times 4$

$\longrightarrow \sf\bold{\red{Second\: number =\: 24}}$

${\small{\bold{\underline{\therefore\: The\: numbers\: are\: 20\: and\: 24\: .}}}}$

Hence, the correct options is option no (d) 20, 24.

Answer 2

Answer:

मृदा अल्पधीत नष्ट होऊ नये म्हणून उपाय सुचवा