maas of ethanol to be added to 1.0kg water to have the mole fraction of ethanol equal to 0.20 ?
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Answer:
638.89g
Explanation:
0.2=m/46gmol−1)(m/46gmol−1)+(1000g/18gmol−1)
⇒m46g=0.2×100018×10.8=13.89
m=13.89×46g=638.89g
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