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Two resistors of 6Ω are connected in parallel with a battery of 6V.
We have to find total current in the circuit..
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◈ First of all, we need to find equivalent resistance of the parallel connection.
Equivalent resistance of parallel connectiom is given by
1/Rp = 1/R₁ + 1/R₂ + ... + 1/Rn
⇒ 1/Rp = 1/R₁ + 1/R₂
⇒ 1/Rp = 1/6 + 1/6
⇒ 1/Rp = 2/6
⇒ Rp = 3Ω
As per ohm's law, current flow in the circuit is directly proportional to the applied potential difference.
V = I × R
➝ V = I × Rp
➝ 6 = I × 3
➝ I = 6/3
➝ I = 2 A
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