Question

machine can take out 1000 kilogram of mud per hour from a depth of 100m . if efficiency of the machine is 0.9. calculate the power​

Answer 1

Answer:

249.993 or 250watt

Explanation:

$power = \frac{work \: done}{time \: taken \: to \: do \: work} \\ \\ here \\ workdone = mgh = 1000 \times 100 \times 10 \\ w = 1 \times 10 {}^{6} \\ \\ time \: given = 60 \times 60 = 3600s \\ power = \frac{ 1 \times {10}^{6} }{3600} = 277.77watt \\ \\ efficiency = 0.9 = 90\% \\ power \: actual = power \times efficiency \\ power = 277.77 \times 0.9 \\ power = 249.993 = 250watt$

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Answer 2

The power is 308.56 W.

Explanation:

The power of the machine is define as

$P=\frac{W}{t}$

Here w is the energy and t is the time taken.

Energy is given as

W = mgh.

Given m =1000 kg, h = 100 m and t = 1 hour = 3600 s and we take g = 10 m/s^2.

so,

$W=1000 kg\times10m/s^2\times100m$

W = 1000000 J.

Hence, power will be

$P=\frac{1000000J}{3600s}$

P = 277.7 W.

Now with 90% efficiency of the machine the power is

$= \frac{277.7 W}{0.9}$

= 308.56 W

Thus, the power is 308.56 W.

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