Math, asked by khalifakhalifa5666, 4 months ago

machinery worth 12000 depriciated by 13% find its value after 3 years

Answers

Answered by Anonymous

2

Answer:

Present cost of machine = Rs.32000 Depreciation percentage every year = 5% So, depreciation at the end of first year = 32000×5/100 = 1600/- Then cost of machine at the end of first year = Rs.32000 - Rs.1600 = Rs.30400/- So, the depreciation amount at the end of second year = 30400×5/100 = 1520/- Therefore, total depreciation at the end of 2 years = Rs.1600 + Rs.1520 = Rs.3120/-

Step-by-step explanation:

Previous Question

Next Question

Similar questions

Science, 2 months ago

Diet differs from person to person. What are the reasons for that ?

English, 2 months ago

АЛs a comprehension passage (Any ten] Floods are not new to India and this sub- continent In recent years the problem has received much greater attention because it has led to much greater damage than in the past Even though information on the impending occurrence of floods is riow more accurate and certainly more timely. often there is very little time to minimize the damage. In the case of...

Accountancy, 2 months ago

आय-व्यय खाता है- A) व्यक्तिगत खाता C) नाममात्र खाता (B) वास्तविक खाता (D) इनमें से कोई नहीं ...

Science, 4 months ago

water :1 .36 :: alcohol :...

History, 4 months ago

which party did not particpate in the kilafat non co operation movement...

Math, 9 months ago

what is the formula to find the perimeter of octagon...

Physics, 9 months ago

if the radius of its orbit is made One by fourth then duration of year will be how many times...

Math, 9 months ago

6. Prove that of all parallelograms of given sides, the rectangle has the maximum area. 7. Prove that the diagonals of a parallelogram divides it into four triangles of equal areas. 8. The diagonals AC and BD of a quadrilateral ABCD intersect at point '0' and the quadrilateral divides into four triangles of equal areas. Prove that ABCD is a parallelogram. 9. The diagonal AC of a quadrilateral...