machinery worth RS 10000 depreciated by5%.find its value after 1 year.
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Answered by
210
Formula is a = p(1-r/100)^n --------------------- (i)
Given p = 10000, r = 5, n = 2
On submitting values in (i), we get
a = 10000(1-5/100)^1
= 10000(95/100)
= 9500 rs.
Hope this helps!
Given p = 10000, r = 5, n = 2
On submitting values in (i), we get
a = 10000(1-5/100)^1
= 10000(95/100)
= 9500 rs.
Hope this helps!
jayanth6:
thanks
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Answered by
77
hi....
Here is your answer.
Here is your answer.
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