Machines A and B produce 8000 chips in 4 and 6 hrs respectively. If they work
anternatively for 1 hr, A starting first, then 8000 chips will be produced
in........hrs.
Answers
≡QUESTION≡
Machines A and B produce 8000 clips in 4 hr and 6 hr respectively. The machines work in alternate hours. If A starts first, then how much time will be required to produce 8000 clips?
║⊕ANSWER⊕║
Work Rate of A = 8000/4
= 2000 clips per hour
Work Rate of B = 8000/6
= 1333.33 clips per hour
Let, 2 hour = 1 unit of time.
Work rate of A and B together = 2000 + 1333.33
= 3333.33 clips per unit time
In two work unit of time, clips created = 2 * 3333.33
= 6666.66 unit
Rest unit = 1333.34
It will be completed by A in,
= 1333.34/2000
= 0.66 hours
= 40 min
Total time taken = 2 unit of time + 40 min
= 2 *2 + 40
= 4 hour and 40 min